3.
Si nos dan los siguientes datos: f(-1)=0, f(0)=-2, f(2)=2 y f(4)= 10, el polinomio de interpolación de Lagrange mediante la formula de Newton es:
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A.
p(x)= 10+4(x-4)+ (1/2)(x-4)(x-2)- (1/6)(x-4)(x-2)x
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B.
p(x)= (-2)x+(4/3)(x-2)(x+1)-(1/6)(x+1)(x-2)x
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C.
p(x)= (-2)(x+1)+ (4/3)(x+1)x –(1/6)(x+1)(x-2)x